PYQSide ExamsMy practice

Trigonometric Functions · Question 1

JEE Advanced 2026 Paper 1NumericalHard📈 Topic in 33% papers+4
1

Let = (1 - 2 ( 11 ) ) (1 - 2 ( 3 11 ) ) (1 - 2 ( 9 11 ) ) (1 - 2 ( 27 11 ) ) (1 - 2 ( 81 11 ) ). Then the value of 5 - 2 is .

Answer

3.9 to 4.1

Solution

Identity: 1 - 2 = - 3 2 2 (since 4 2 2 - 3 = 2 - 1).

With k = 3k 11, k = 0, , 4, the product telescopes:

= (-1)5 35 22 22

243 22 = 11 + 22 243 22 = - 22

= (-1)(-1) = 1, so 5 - 2 = 4

Answer: 4

JEE Advanced 2026 Paper 1

Keep practising — Trigonometric Functions

2

Match each entry in List-I to the correct entry in List-II and choose the correct option.

  1. (P) → (2), (Q) → (5), (R) → (3), (S) → (4)
  2. (P) → (5), (Q) → (3), (R) → (2), (S) → (4)
  3. (P) → (5), (Q) → (4), (R) → (1), (S) → (3)
  4. (P) → (4), (Q) → (3), (R) → (2), (S) → (5)
JEE Advanced 2026 Paper 1
3

The value of n is .

JEE Advanced 2026 Paper 2
4

Let = 1 60 61 + 1 62 63 + + 1 118 119 . Then the value of ( cosec1 )2 is .

JEE Advanced 2025 Paper 2
5

Let 2<x< be such that x= -5 11. Then ( 11x2 ) ( 6x- 6x )+ ( 11x2 ) ( 6x+ 6x ) is equal to

  1. 11-12 3
  2. 11+12 3
  3. 11+13 2
  4. 11-13 2
JEE Advanced 2024 Paper 1
6

Let f: R R be a function defined by f(x)= cases x2 ( x2 ), & if x 0,\ 0, & if x=0. cases Then which of the following statements is TRUE?

  1. f(x)=0 has infinitely many solutions in the interval [ 11010, ).
  2. f(x)=0 has no solutions in the interval [ 1 , ).
  3. The set of solutions of f(x)=0 in the interval (0, 11010 ) is finite.
  4. f(x)=0 has more than 25 solutions in the interval ( 1 2, 1 ).
JEE Advanced 2024 Paper 2

All Trigonometric Functions PYQs →

PDFDownload Trigonometric Functions PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Advanced Mathematics chapters