There are two vessels filled with an ideal gas where volume of one is double the volume of the other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K. If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K, at steady state the pressure in the vessels will be (in kPa).
- 24
- 4.4
- 18
- 6
Answer
(4) 6
Solution
Let the volume of the smaller vessel be V, so the larger one has 2V. From n = PVRT:
n1 = 8 2VR 1000, n2 = 7 VR 500
The total number of moles does not change. At steady state the common pressure is P in total volume 3V at 600 K:
P 3VR 600 = 16V1000R + 7V500R
P200 = 0.016 + 0.014 = 0.030
P = 6 kPa
Answer: (4)