'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol-1 when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and Kb for water is 0.52 K kg mol-1, then the mole fraction of the electrolyte solute (x2) in the solution can be expressed as (Given : density of water = 1 g/mL and boiling point of water = 373 K)
- 162.6 WM
- 1.38 MW
- 2.616 MW
- 1.38 WM
Answer
(4) 1.38 WM
Solution
Mass of water = 100 mL 1 g/mL = 100 g = 0.1 kg
Molality, m = W/M0.1 = 10WM mol kg-1
Elevation of boiling point (electrolyte, van't Hoff factor i):
Tb = 375 - 373 = 2 K = i Kb m
2 = i 0.52 10WM
i = 25.2 MW
Relative lowering of vapour pressure (dilute solution):
p - pp = i x2
640 - 600640 = 116 = i x2
x2 = 116 i = 116 5.22 WM = 2.616 WM
x2 = 1.38 WM
Answer: (4)