In which pairs, the first ion is more stable than the second?
- (A) & (B) only
- (B) & (D) only
- (A) & (C) only
- (B) & (C) only
Answer
(1) (A) & (B) only
Solution
(A) First: the lone pair of –OMe oxygen delocalises onto C (+R), giving a structure in which every atom has an octet ( O=C). Second: only +I and hyperconjugation of –Me.
First is more stable. ✓
(B) First: the carbanion is conjugated with the benzene ring bearing an ortho –NO2 group; the negative charge is delocalised onto the ring and the nitro oxygens (–R, –I) highly stabilised.
Second: the carbocation is attached to a ring bearing an ortho –NO2 group, whose –R and –I effects destabilise the positive charge.
First is more stable. ✓
(C) First: a primary carbocation (only +I / hyperconjugation). Second: the CH2 is attached to a C=C (allylic carbocation), stabilised by resonance.
Second is more stable. ✗
(D) First: tert-butyl carbocation (+I and 9 hyperconjugating H). Second: –OMe on C gives +R stabilisation, which outweighs hyperconjugation.
Second is more stable. ✗
(A) & (B) only.
Answer: (1)