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Hydrocarbons · Question 51

AIPMT 2004MCQMedium📈 Topic in 12% papers+4−1
1

Using anhydrous AlCl3 as catalyst, which one of the following reactions produces ethylbenzene (PhEt)?

  1. H3C-CH2OH + C6H6
  2. CH3-CH=CH2 + C6H6
  3. H2C=CH2 + C6H6
  4. H3C-CH3 + C6H6

Answer

(3) H2C=CH2 + C6H6

Solution

With anhydrous AlCl3 (and a trace of HCl), ethene forms the ethyl carbocation, which alkylates benzene (Friedel–Crafts type alkylation):

H2C=CH2 + HCl + AlCl3 CH3- CH2 + AlCl4

C6H6 + CH3 CH2 C6H5-CH2CH3 + H

Propene would give isopropylbenzene (cumene), ethane does not react, and ethanol deactivates AlCl3.

Answer: (3)

AIPMT 2004

Keep practising — Hydrocarbons

2

Reaction of HBr with propene in the presence of peroxide gives

  1. isopropyl bromide
  2. 3-bromopropane
  3. allyl bromide
  4. n-propyl bromide
AIPMT 2004
3

The compound CH3- CH3 |C=CH-CH3 on reaction with NaIO4 in the presence of KMnO4 gives

  1. CH3COCH3
  2. CH3COCH3 + CH3COOH
  3. CH3COCH3 + CH3CHO
  4. CH3CHO + CO2
AIPMT 2003
4

The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is

  1. III > II > I
  2. II > III > I
  3. I < II > III
  4. I > II > III
AIPMT 2003
5

When CH3CH2CHCl2 is treated with NaNH2, the product formed is

  1. CH3-CH=CH2
  2. CH3-C CH
  3. [figure]
  4. [figure]
AIPMT 2002
6

Which alkene on ozonolysis gives CH3CH2CHO and CH3COCH3?

  1. [figure]
  2. CH3CH2CH=CHCH2CH3
  3. CH3CH2CH=CHCH3
  4. [figure]
AIPMT 2001
7

Increasing order of electrophilic substitution for following compounds [figure]

  1. IV < I < II < III
  2. III < II < I < IV
  3. I < IV < III < II
  4. II < III < I < IV
AIPMT 2000
8

In Friedel-Crafts reaction, toluene can be prepared by

  1. C6H6 + CH3Cl
  2. C6H5Cl + CH4
  3. C6H6 + CH2Cl2
  4. C6H6 + CH3COCl
AIPMT 2000

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