Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is
- 23Ml2
- 133Ml2
- 13Ml2
- 43Ml2
Answer
(4) 43Ml2
Solution
Moment of inertia of one rod about an axis through its own centre, perpendicular to its length:
Icm = Ml212
The centre of each rod is at a distance l2 from the centre of the square. By the theorem of parallel axes:
Irod = Ml212 + M ( l2 )2
Irod = Ml212 + Ml24 = Ml23
For the four rods:
I = 4 Ml23 = 43Ml2
Answer: (4)