Let f(x) = cases ax2 + 2ax + 34x2 + 4x - 3 & , x - 32, 12 \ b & , x = - 32, 12 cases be continuous at x = - 32. If f f(x) = 75, then x is equal to:
- 1.4
- 2
- 1
- 0
Answer
(3) 1
Solution
4x2 + 4x - 3 = (2x + 3)(2x - 1) vanishes at x = - 32, so for a finite limit the numerator must also vanish there:
a 94 - 3a + 3 = 0 a = 4
4x2 + 8x + 3 = (2x + 3)(2x + 1)
f(x) = 2x + 12x - 1, x - 32, 12
Continuity at x = - 32: b = -3 + 1-3 - 1 = 12
Let f(x) = t. f(t) = 75 b, so t - 32, 12:
2t + 12t - 1 = 75 10t + 5 = 14t - 7 t = 3
2x + 12x - 1 = 3 2x + 1 = 6x - 3 x = 1
Answer: (3)