The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is
- 2 : 1
- 2 : 1
- 4 : 1
- 1 : 2
Answer
(2) 2 : 1
Solution
About the axis through the centre and normal to the plane: I1 = 12MR2 = Mk12 k1 = R 2
About a diameter (perpendicular axis theorem): I2 = 14MR2 = Mk22 k2 = R2
k1k2 = R/ 2R/2 = 2 2 = 2
k1 : k2 = 2 : 1
Answer: (2)