Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :
- 103 m
- 203 m
- 10 m
- 5 m
Answer
(2) 203 m
Solution
Take the 10 kg mass at x = 0 and the 20 kg mass at x = 10 m.
xcm = 10 0 + 20 1010 + 20
= 20030 = 203 m
Answer: (2)