Let , R be such that the system of linear equations x+2y+z=5 2x+y+ z=5 8x+4y+ z=18 has no solution. Then is equal to :
- -4
- 4
- 8
- -8
Answer
(2) 4
Solution
For no solution, the coefficient determinant must vanish:
= vmatrix1&2&1\\2&1& \\8&4& vmatrix=1( -4 )-2(2 -8 )+1(8-8)
=12 -3 =0 =4
Check: with =4 , the third equation is 8x+4y+4 z=18,
while 4 (second equation) gives 8x+4y+4 z=20.
∵ 18 20, these two planes are parallel and distinct, so the system has no solution for every 0.
∴ =4
Answer: (2)