Let P = [pij] and Q = [qij] be two square matrices of order 3 such that qij = 2(i+j-1)pij and (Q) = 210. Then the value of ( adj( adj P)) is:
- 81
- 16
- 124
- 32
Answer
(2) 16
Solution
qij = 2-1 2i 2j pij
Taking 2-1 out of every entry, 2i out of row i and 2j out of column j:
(Q) = (2-1)3 21+2+3 21+2+3 (P) = 29 (P)
⇒ 29 (P) = 210 ⇒ (P) = 2
For a matrix of order n: ( adj( adj P)) = ( P)(n-1)2
∴ ( adj( adj P)) = 2(3-1)2 = 24 = 16
Answer: (2)