In a vernier callipers, 20 VSD coincide with 16 MSD (each division of length 1 mm). The least count of the vernier callipers is :
- 0.2 cm
- 0.1 cm
- 0.02 cm
- 0.01 cm
Answer
(3) 0.02 cm
Solution
1 VSD = 1620 MSD = 0.8 mm
LC = 1 MSD − 1 VSD = 1 − 0.8 = 0.2 mm = 0.02 cm
Answer: (3)