Each side of a metallic cube of mass 5.580 kg is measured to be 9.0 cm. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X 103 kg m-3, where the value of X is :
- 7.654
- 7.7
- 7.65
- 7.6
Answer
(2) 7.7
Solution
= 5.580(9.0 10-2)3
⇒ = 5.5807.29 10-4 = 7.654 103 kg m-3
∵ Side 9.0 cm has only 2 significant figures ⇒ the result is rounded off to 2 significant figures.
∴ = 7.7 103 kg m-3, X = 7.7
Answer: (2)