The electric field in a certain region is acting radially outward and is given by E = Ar. A charge contained in a sphere of radius 'a' centred at the origin of the field, will be given by
- 4 0 Aa3
- 0 Aa3
- 4 0 Aa2
- A 0 a2
Answer
(1) 4 0 Aa3
Solution
At the surface of the sphere (r = a): E = Aa, directed radially outward.
Flux through the sphere: = E 4 a2 = Aa 4 a2 = 4 Aa3
By Gauss's law: = q 0
q = 4 0 Aa3
Answer: (1)