Which of the following happens when NH4OH is added gradually to the solution containing 1 M A2+ and 1M B3+ ions? Given : Ksp [A(OH)2] = 9 10-10 and Ksp [B(OH)3] = 27 10-18 at 298 K.
- A(OH)2 will precipitate before B(OH)3
- A(OH)2 and B(OH)3 will precipitate together
- Both A(OH)2 and B(OH)3 do not show precipitation with NH4OH
- B(OH)3 will precipitate before A(OH)2
Answer
(4) B(OH)3 will precipitate before A(OH)2
Solution
Concept: the hydroxide needing the smaller [OH-] precipitates first.
A(OH)2: [OH-] = 9 10-10 = 3 10-5 M
B(OH)3: [OH-] = (27 10-18)1/3 = 3 10-6 M
3 10-6 < 3 10-5 ⇒ B(OH)3 precipitates first.
Answer: (4)