In hydrogen spectrum, the shortest wavelength in the Balmer series is . The shortest wavelength in the Brackett series is :
- 4
- 9
- 16
- 2
Answer
(1) 4
Solution
Shortest wavelength of a series: ni , so 1 = Rnf2
Balmer series (nf = 2): = 4R
Brackett series (nf = 4): ' = 16R
' = 164 = 4
' = 4
Answer: (1)