Given the value of Rydberg constant is 107 m-1, the wave number of the last line of the Balmer series in hydrogen spectrum will be
- 0.25 107 m-1
- 2.5 107 m-1
- 0.025 104 m-1
- 0.5 107 m-1
Answer
(1) 0.25 107 m-1
Solution
Wave number: = R ( 1nf2 - 1ni2 )
For the last line of the Balmer series: nf = 2, ni =
= R4 = 1074
= 0.25 107 m-1
Answer: (1)