When an -particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach from the nucleus depends on m as
- 1m2
- m
- 1m
- 1 m
Answer
(3) 1m
Solution
At closest approach, kinetic energy = potential energy:
12mv2 = 14 0 (2e)(Ze)r0
r0 = 4Ze24 0 mv2
r0 1m
Answer: (3)