A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5 m. The impulse of force imparted by the ground to the body is given by : (given, g=9.8 m/s2)
- 43.2 kg ms-1
- 2.39 kg ms-1
- 4.32 kg ms-1
- 23.9 kg ms-1
Answer
(2) 2.39 kg ms-1
Solution
Speed just before impact: v1= 2gh1= 2 9.8 10=14 m/s (down)
Speed just after impact: v2= 2gh2= 2 9.8 5=7 2 9.9 m/s (up)
Impulse = change in momentum, direction reversed
J=m (v2+v1 )=0.1 (9.9+14 )
2.39 kg ms-1
Answer: (2)