A block of mass m is placed on a surface having vertical cross-section given by y=x2/4. If coefficient of friction is 0.5, the maximum height above the ground at which block can be placed without slipping is:
- 1/2 m
- 1/3 m
- 1/6 m
- 1/4 m
Answer
(4) 1/4 m
Solution
[figure]
No slipping: mg mg
Slope of surface: = dydx= x2
x2 0.5 x 1 m
h =y(1)= 124= 14 m
Answer: (4)