Two adjacent sides of a parallelogram PQRS are given by PQ= j+ k and PS= i- j. If the side PS is rotated about the point P by an acute angle in the plane of the parallelogram so that it becomes perpendicular to the side PQ, then 2 ( 5 2 )- 2 ( 2 ) is equal to:
- 12
- 32
- 34
- 2 35
Answer
(2) 32
Solution
QPS= PQ PS| PQ|| PS|= ( j+ k) ( i- j) 2 2=- 12
QPS=120
To become perpendicular to PQ, PS must turn (in the same plane) towards PQ through 120 -90 =30 , which is acute.
=30 5 2=75 , 2=15
2A- 2B= (A+B) (A-B)
2 75 - 2 15 = 90 60 = 32
Answer: (2)