Let a = 2 i - j - k, b = i + 3 j - k and c = 2 i + j + 3 k. Let v = a + b, R, be the vector in the plane of the vectors a and b, such that the length of its projection on the vector c is 1 14. Then | v| is equal to
- 352
- 13
- 212
- 7
Answer
(1) 352
Solution
v = a + b, | c| = 4 + 1 + 9 = 14
a c = 4 - 1 - 3 = 0, b c = 2 + 3 - 3 = 2
v c = 0 + 2 = 2
Length of projection = | v c|| c| = |2 | 14 = 1 14
| | = 12, i.e. 2 = 14
Now | a|2 = 6, | b|2 = 11, a b = 2 - 3 + 1 = 0
| v|2 = | a|2 + 2| b|2 + 2 ( a b)
= 6 + 114 + 0 = 354
| v| = 352
Answer: (1)