Let AB = 2 i + 4 j - 5 k and AD = i + 2 j + k, R. Let the projection of the vector v = i + j + k on the diagonal AC of the parallelogram ABCD be of length one unit. If , , where > , be the roots of the equation 2x2 - 6 x + 5 = 0, then 2 - is equal to
- 3
- 6
- 4
- 1
Answer
(1) 3
Solution
AC = AB + AD = 3 i + 6 j + ( - 5) k
Projection of v on AC:
3 + 6 + - 5 9 + 36 + ( - 5)2 = 1
( + 4)2 = 45 + ( - 5)2
2 + 8 + 16 = 2 - 10 + 70
18 = 54 = 3
Equation: 9x2 - 18x + 5 = 0
(3x - 1)(3x - 5) = 0 x = 53, 13
= 53, = 13
2 - = 103 - 13 = 3
Answer: (1)