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Haloalkanes and Haloarenes

JEE Main 2024 (Online) 9th April Evening ShiftMCQMedium📈 Topic in 31% papers+4−1
Ques. 1JEE Main 2024, 9 April (Evening Shift)

[figure] In the above reaction product 'P' is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(1) [figure]

Solution

The phenyl ring on the neighbouring carbon takes part in the reaction (neighbouring group participation, NGP). Its π electrons push out Br- from the back side and a bridged phenonium ion is formed. CN- then opens the three-membered ring at the carbon carrying –OCH3, because this carbon holds the positive charge better (lone pair of O), and the ring becomes aromatic again:

[figure]

So the phenyl group stays on its own carbon and CN simply takes the place of Br; the carbon skeleton does not change.

∴ P = C6H5CH(CH3)CH(OCH3)CN, which is structure (1).

(2), (3) and (4) need a phenyl, methyl or –OCH3 shift, which does not take place here, so they are wrong.

Answer: (1)

Keep practising — Haloalkanes and Haloarenes

Ques. 2JEE Main 2024, 8 April (Morning Shift)

Which among the following compounds will undergo fastest SN2 reaction.

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Ques. 3JEE Main 2024, 8 April (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are false
  2. Statement I is false but Statement II is true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are true
Ques. 4JEE Main 2024, 6 April (Morning Shift)

Match List I with List II Choose the correct answer from the options given below:

  1. A-II, B-IV, C-I, D-III
  2. A-III, B-I, C-IV, D-II
  3. A-III, B-II, C-IV, D-I
  4. A-I, B-II, C-III, D-IV
Ques. 5JEE Main 2024, 6 April (Morning Shift)

The major products from the following reaction sequence are product A and product B. [figure] The total sum of electrons in product A and product B are (nearest integer)

Ques. 6JEE Main 2024, 6 April (Evening Shift)

[figure] Consider the above chemical reaction. Product "A" is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 7JEE Main 2024, 5 April (Morning Shift)

The number of halobenzenes from the following that can be prepared by Sandmeyer's reaction is [figure]

Ques. 8JEE Main 2024, 5 April (Evening Shift)

Identify the major product in the following reaction. [figure]

  1. [figure]
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Ques. 9JEE Main 2024, 4 April (Morning Shift)

[figure] Identify B and C and how are A and C related?

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Ques. 10JEE Main 2024, 4 April (Morning Shift)

Identify the correct set of reagents or reaction conditions 'X' and 'Y' in the following set of transformation. CH3-CH2-CH2-Br 'X' Product 'Y' CH3- Br |CH-CH3

  1. X = dil.aq. NaOH, 20°C, Y = HBr/ acetic acid
  2. X = conc.alc. NaOH, 80°C, Y = Br2/CHCl3
  3. X = dil.aq. NaOH, 20°C, Y = Br2/CHCl3
  4. X = conc.alc. NaOH, 80°C, Y = HBr/ acetic acid
Ques. 11JEE Main 2024, 4 April (Evening Shift)

[figure] Product P is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

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