PYQSidePowered byPrepblink ExamsMy practice

Haloalkanes and Haloarenes

JEE Main 2024 (Online) 5th April Morning ShiftNumericalEasy📈 Topic in 5% papers+4
Ques. 1JEE Main 2024, 5 April (Morning Shift)

The number of halobenzenes from the following that can be prepared by Sandmeyer's reaction is [figure]

Answer

2

Solution

Sandmeyer reaction: C6H5N2+X- Cu2Cl2/HCl C6H5Cl ; C6H5N2+X- Cu2Br2/HBr C6H5Br

I (F): needs HBF4 then heat (Balz–Schiemann) ⇒ I is not Sandmeyer

II (Cl), III (Br): Cu(I) halide ⇒ II and III are Sandmeyer products

IV (I): KI alone, no Cu(I) salt ⇒ IV is not Sandmeyer

V (At): radioactive, not made this way ⇒ V is not Sandmeyer

Answer: 2

Keep practising — Haloalkanes and Haloarenes

Ques. 2JEE Main 2024, 5 April (Evening Shift)

Identify the major product in the following reaction. [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 3JEE Main 2024, 4 April (Morning Shift)

[figure] Identify B and C and how are A and C related?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2024, 4 April (Morning Shift)

Identify the correct set of reagents or reaction conditions 'X' and 'Y' in the following set of transformation. CH3-CH2-CH2-Br 'X' Product 'Y' CH3- Br |CH-CH3

  1. X = dil.aq. NaOH, 20°C, Y = HBr/ acetic acid
  2. X = conc.alc. NaOH, 80°C, Y = Br2/CHCl3
  3. X = dil.aq. NaOH, 20°C, Y = Br2/CHCl3
  4. X = conc.alc. NaOH, 80°C, Y = HBr/ acetic acid
Ques. 5JEE Main 2024, 4 April (Evening Shift)

[figure] Product P is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 6JEE Main 2024, 4 April (Evening Shift)

Find out the major product formed from the following reaction. [Me : –CH3] [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 7JEE Main 2024, 1 February (Morning Shift)

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. (A) is correct but (R) is not correct
  2. Both (A) and (R) are correct and (R) is the correct explanation of (A)
  3. (A) is not correct but (R) is correct
  4. Both (A) and (R) are correct but (R) is not the correct explanation of (A)
Ques. 8JEE Main 2024, 1 February (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
  2. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  3. (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  4. (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Ques. 9JEE Main 2024, 31 January (Morning Shift)

The product (C) in the below mentioned reaction is : CH3-CH2-CH2-Br [ ]KOH(alc) A HBr B [KOH(aq)] C

  1. Propan-1-ol
  2. Propyne
  3. Propan-2-ol
  4. Propene
Ques. 10JEE Main 2024, 31 January (Morning Shift)

[figure] The total number of hydrogen atoms in product A and product B is .

Ques. 11JEE Main 2024, 31 January (Evening Shift)

Identify structure of 2,3-dibromo-1-phenylpentane.

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

All Haloalkanes and Haloarenes PYQs →

PDFDownload Haloalkanes and Haloarenes PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Chemistry chapters
Physical ChemistrySome Basic Concepts of ChemistryStructure of AtomStates of MatterThermodynamicsEquilibriumRedox ReactionsSolid StateSolutionsElectrochemistryChemical Kinetics
Inorganic ChemistryClassification of Elements and Periodicity in PropertiesChemical Bonding and Molecular Structures-Block Elementsp-Block Elements (Group 13 & 14)Environmental ChemistryGeneral Principles of Isolation of Elementsp-Block Elements (Group 15–18)d- and f-Block ElementsCoordination Compounds
Organic ChemistryOrganic Chemistry – Some Basic Principles and TechniquesIsomerismHydrocarbonsHaloalkanes and HaloarenesAlcohols, Phenols and EthersAldehydes, Ketones and Carboxylic AcidsAminesBiomoleculesPrinciples Related to Practical Chemistry