The molecular formula of second homologue in the homologous series of mono carboxylic acids is
- C2H4O2
- C2H2O2
- CH2O
- C3H6O2
Answer
(1) C2H4O2
Solution
Monocarboxylic acids: CnH2n+1COOH (n = 0, 1, 2, …); successive members differ by -CH2-
First member: HCOOH (CH2O2)
Second member: CH3COOH ⇒ C2H4O2
Answer: (1)