A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75\% of octahedral voids. The formula of the compound is :
- C3A4
- C4A3
- C2A3
- C3A
Answer
(1) C3A4
Solution
In a close packed lattice, number of octahedral voids = number of anions.
Let the number of anions A = N; octahedral voids = N
Number of cations C = 75100 N = 34N
C : A = 34N : N = 3 : 4
Formula = C3A4
Answer: (1)