A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm-3. The molar mass of the metal is (NA Avogadro's constant = 6.02 1023 mol-1)
- 27 g mol-1
- 20 g mol-1
- 40 g mol-1
- 30 g mol-1
Answer
(1) 27 g mol-1
Solution
d = Z Ma3 NA
M = d a3 NAZ
For fcc, Z = 4; a = 404 pm = 4.04 10-8 cm
a3 = 65.94 10-24 cm3
M = 2.72 65.94 10-24 6.02 10234
= 107.974
27 g mol-1
Answer: (1)