CsBr crystallises in a body centered cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro number being 6.02 1023 mol-1, the density of CsBr is
- 4.25 g/cm3
- 42.5 g/cm3
- 0.425 g/cm3
- 8.25 g/cm3
Answer
(1) 4.25 g/cm3
Solution
In the CsBr unit cell, Cs+ is at the body centre and Br- ions are at the 8 corners.
⇒ Number of Br- = 8 18 = 1, number of Cs+ = 1
∴ Z = 1 formula unit of CsBr per unit cell
M = 133 + 80 = 213 g mol-1
a = 436.6 pm = 4.366 10-8 cm
a3 = (4.366 10-8)3 = 8.322 10-23 cm3
d = Z Ma3 NA
= 1 2138.322 10-23 6.02 1023
= 21350.10
= 4.25 g/cm3
Answer: (1)