If dxdy= 1+x-y2y,x(1)=1, then 5x(2) is equal to .
Answer
5
Solution
Linear in x: dxdy- xy= 1-y2y
I.F. =e- 1ydy= 1y
xy= ( 1y2-1 )dy=- 1y-y+C
x=-1-y2+Cy
x(1)=1 1=-2+C =3
x(2)=-1-4+6=1 5x(2)=5
Answer: 5
If dxdy= 1+x-y2y,x(1)=1, then 5x(2) is equal to .
5
Linear in x: dxdy- xy= 1-y2y
I.F. =e- 1ydy= 1y
xy= ( 1y2-1 )dy=- 1y-y+C
x=-1-y2+Cy
x(1)=1 1=-2+C =3
x(2)=-1-4+6=1 5x(2)=5
Answer: 5
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