An alternating electric field, of frequency , is applied across the dees (radius = R) of a cyclotron that is being used to accelerate protons (mass = m). The operating magnetic field (B) used in the cyclotron and the kinetic energy (K) of the proton beam, produced by it, are given by
- B = m e and K = 2m 2 2R2
- B = 2 e and K = m2 2
- B = 2 e and K = 2m 2 2R2
- B = m e and K = m2 2
Answer
(3) B = 2 e and K = 2m 2 2R2
Solution
Cyclotron frequency (equal to the frequency of the applied field):
= eB2
B = 2 e
At the edge of the dees (radius R): R = mveB v = eBRm = 2
K = 12mv2 = 12m(2 )2
K = 2m 2 2R2
Answer: (3)