A millivoltmeter of 25 millivolt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be
- 0.001
- 0.01
- 1
- 0.05
Answer
(1) 0.001
Solution
At full scale, the potential difference across the meter (and across the shunt in parallel with it) is V = 25 mV = 25 10-3 V.
The current through the meter itself is negligible, so almost the whole 25 A flows through the shunt:
S = VI = 25 10-325
S = 0.001
Answer: (1)