A galvanometer of resistance, G, is shunted by a resistance S ohm. To keep the main current in the circuit unchanged, the resistance to be put in series with the galvanometer is
- G(S+G)
- S2(S+G)
- ( SGS+G )
- G2(S+G)
Answer
(4) G2(S+G)
Solution
Before shunting, the resistance in the circuit due to the galvanometer is G.
After shunting, the effective resistance = SGS+G
To keep the main current unchanged, the total resistance must remain G:
R + SGS+G = G
R = G - SGS+G = G2S+G
Answer: (4)