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p-Block Elements (Group 15–18) · Question 28

NEET 2017MCQEasy📈 Topic in 38% papers+4−1
1

Name the gas that can readily decolourise acidified KMnO4 solution.

  1. SO2
  2. NO2
  3. P2O5
  4. CO2

Answer

(1) SO2

Solution

As per NCERT, moist sulphur dioxide behaves as a reducing agent and decolourises acidified potassium permanganate(VII) solution; this is a convenient test for the gas.

5SO2 + 2MnO4- + 2H2O 5SO42- + 4H+ + 2Mn2+

CO2 and P2O5 are not reducing, and NO2 is mainly an oxidising agent.

Answer: (1)

NEET 2017

Keep practising — p-Block Elements (Group 15–18)

2

HgCl2 and I2 both when dissolved in water containing I- ions, the pair of species formed is

  1. HgI2, I-
  2. HgI42-, I3-
  3. Hg2I2, I-
  4. HgI2, I3-
NEET 2017
3

Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option

  1. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
  2. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  3. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  4. (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)
NEET 2016 (Phase 1)
4

Which is the correct statement for the given acids?

  1. Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acid.
  2. Phosphinic acid is a diprotic acid while phosphonic acid is a monoprotic acid.
  3. Both are diprotic acids.
  4. Both are triprotic acids.
NEET 2016 (Phase 1)
5

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?

  1. Br2 > I2 > F2 > Cl2
  2. F2 > Cl2 > Br2 > I2
  3. I2 > Br2 > Cl2 > F2
  4. Cl2 > Br2 > F2 > I2
NEET 2016 (Phase 1)
6

When copper is heated with conc. HNO3 it produces

  1. Cu(NO3)2, NO and NO2
  2. Cu(NO3)2 and N2O
  3. Cu(NO3)2 and NO2
  4. Cu(NO3)2 and NO
NEET 2016 (Phase 1)
7

Among the following the correct order of acidity is

  1. HClO2 < HClO < HClO3 < HClO4
  2. HClO4 < HClO2 < HClO < HClO3
  3. HClO3 < HClO4 < HClO2 < HClO
  4. HClO < HClO2 < HClO3 < HClO4
NEET 2016 (Phase 1)
8

Hot concentrated sulphuric acid is a moderately strong oxidizing agent. Which of the following reactions does not show oxidizing behaviour?

  1. Cu + 2H2SO4 CuSO4 + SO2 + 2H2O
  2. 3S + 2H2SO4 3SO2 + 2H2O
  3. C + 2H2SO4 CO2 + 2SO2 + 2H2O
  4. CaF2 + H2SO4 CaSO4 + 2HF
NEET 2016 (Phase 2)
9

Strong reducing behavior of H3PO2 is due to

  1. high electron gain enthalpy of phosphorus
  2. high oxidation state of phosphorus
  3. presence of two -OH groups and one P-H bond
  4. presence of one -OH group and two P-H bonds.
AIPMT 2015
10

The variation of the boiling points of the hydrogen halides is in the order HF > HI > HBr > HCl. What explains the higher boiling point of hydrogen fluoride?

  1. There is strong hydrogen bonding between HF molecules.
  2. The bond energy of HF molecules is greater than in other hydrogen halides.
  3. The effect of nuclear shielding is much reduced in fluorine which polarises the HF molecule.
  4. The electronegativity of fluorine is much higher than for other elements in the group.
AIPMT 2015
11

Which of the statements given below is incorrect?

  1. O3 molecule is bent.
  2. ONF is isoelectronic with O2N-
  3. OF2 is an oxide of fluorine.
  4. Cl2O7 is an anhydride of perchloric acid.
AIPMT 2015

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