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Principles of Inheritance and Variation · Question 97

AIPMT 2010 (Mains)MCQEasy📈 Topic in 50% papers+4−1
1

In Antirrhinum two plants with pink flowers were hybridized. The F1 plants produced red, pink and white flowers in the proportion of 1 red, 2 pink and 1 white. What could be the genotype of the two plants used for hybridization? Red flower colour is determined by RR, and White by rr genes -

  1. rrrr
  2. rr
  3. Rr
  4. RR

Answer

(3) Rr

Solution

In snapdragon ( Antirrhinum), flower colour shows incomplete dominance: RR = red, Rr = pink, rr = white.

⇒ Pink × pink = Rr × Rr

⇒ Progeny: 1 RR (red) : 2 Rr (pink) : 1 rr (white)

∴ Both parent plants were Rr.

Answer: (3)

AIPMT 2010 (Mains)

Keep practising — Principles of Inheritance and Variation

2

Which one of the following symbols and its representation, used in human pedigree analysis is correct –

  1. [figure] = mating between relatives
  2. [figure] = unaffected female
  3. [figure] = unaffected male
  4. [figure] = male affected
AIPMT 2010 (Prelims)
3

ABO blood groups in humans are controlled by the gene I. It has three alleles – IA, IB and i. Since there are three different alleles, six different genotypes are possible. How many phenotypes can occur –

  1. One
  2. Two
  3. Three
  4. Four
AIPMT 2010 (Prelims)
4

Select the correct statement from the ones given below with respect to dihybrid cross –

  1. Genes far apart on the same chromosome show very few recombinations
  2. Tightly linked genes on the same chromosome show very few recombinations
  3. Tightly linked genes on the same chromosome show higher recombinations
  4. Genes loosely linked on the same chromosome show similar recombinations as the tightly linked ones
AIPMT 2010 (Prelims)
5

The genotype of a plant showing the dominant phenotype can be determined by –

  1. Pedigree analysis
  2. Back cross
  3. Test cross
  4. Dihybrid cross
AIPMT 2010 (Prelims)
6

Which one of the following cannot be explained on the basis of Mendel's Law of Dominance?

  1. Out of one pair of factors one is dominant, and the other recessive
  2. Alleles do not show any blending and both the characters recover as such in F2 generation
  3. The discrete unit controlling a particular character is called a factor
  4. Factors occur in pairs
AIPMT 2010 (Prelims)
7

Select the incorrect statement from the following:

  1. Baldness is a sex limited trait
  2. Galactosemia is an inborn error of metabolism
  3. Linkage is an exception to the principle of independent assortment in heredity
  4. Small population size results in random genetic drift in a population
AIPMT 2009
8

Sickle-cell anaemia is:

  1. Caused by substitution of valine by glutamic acid in the beta globin chain of haemoglobin
  2. An autosomal linked dominant trait
  3. Caused by a change in a single base pair of DNA
  4. Characterised by elongated sickle like RBCs with a nucleus
AIPMT 2009
9

The most popularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because "O" in it refers to having:

  1. Other antigens besides A and B on RBCs
  2. No antigens A and B on RBCs
  3. Overdominance of this type on the genes for A and B types
  4. One antibody only – either anti-A or anti-B on the RBCs
AIPMT 2009
10

Study the pedigree chart given below: [figure] What does it show?

  1. Inheritance of a recessive sex-linked disease like haemophilia
  2. Inheritance of a sex-linked inborn error of metabolism like phenylketonuria
  3. The pedigree chart is wrong as this is not possible
  4. Inheritance of a condition like phenylketonuria as an autosomal recessive trait
AIPMT 2009
11

Which one of the following conditions in humans is correctly matched with its chromosomal abnormality/linkage?

  1. Klinefelter's syndrome — 44 autosomes + XXY
  2. Colour-blindness — Y-linked
  3. Down syndrome — 44 autosomes + XO
  4. Erythroblastosis foetalis — X-linked
AIPMT 2008

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