The electric potential as a function of x, y is given by V=5 (x2-y2 ) V. The electric field at a point (2, 3) m is V/m.
- (-20 i+30 j )
- (20 i-30 j )
- (20 i+45 j )
- (-4 i+6 j )
Answer
(1) (-20 i+30 j )
Solution
E=- ( V x i+ V y j )
V=5(x2-y2) ⇒ V x=10x, V y=-10y
⇒ E=-10x i+10y j
At (2, 3): E=-20 i+30 j
∴ E= (-20 i+30 j ) V/m
Answer: (1)