If a and b are two vectors such that | a|=2 and | b|=3, then the maximum value of 3 | (3 a+2 b ) |+4 | (3 a-2 b ) | is :
- 30
- 36
- 60
- 72
Answer
(3) 60
Solution
Let a b=p, where -6 p 6.
|3 a+2 b|2=9(4)+4(9)+12p=72+12p
|3 a-2 b|2=72-12p
|3 a+2 b|2+|3 a-2 b|2=144
∴ Put |3 a+2 b|=12 , |3 a-2 b|=12 , [0, 2 ]
Expression =36 +48 362+482=60
Equality when = 43: |3 a+2 b|= 365
72+12p= 129625 p=-1.68 [-6,6], so it is attained.
∴ Maximum value =60
Answer: (3)