Molar ionic conductivities of divalent cation and anion are 57 S cm2 mol-1 and 73 S cm2 mol-1 respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be:
- 187 S cm2 mol-1
- 260 S cm2 mol-1
- 65 S cm2 mol-1
- 130 S cm2 mol-1
Answer
(4) 130 S cm2 mol-1
Solution
Divalent cation A2+ + divalent anion B2- ⇒ electrolyte AB (e.g. MgSO4): 1 cation + 1 anion per formula unit
Kohlrausch's law: m = + + + - -
⇒ m = 1 57 + 1 73 = 130 S cm2 mol-1
Answer: (4)