In Carius method 0.2425 g of an organic compound gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is
- 87.65%
- 53.58%
- 37.57%
- 34.79%
Answer
(2) 53.58%
Solution
1 mol AgCl (143.32 g) contains 1 mol Cl (35.45 g).
Mass of Cl in 0.5253 g AgCl = 35.45 0.5253143.32 g = 0.1299 g
% Cl = 0.12990.2425 100
% Cl = 53.58%
(With Cl = 35.5 and AgCl = 143.5, % Cl = 53.59% 53.58%.)
Answer: (2)