PYQSidePowered byPrepblink ExamsMy practice

Statistics

JEE Main 2024 (Online) 4th April Morning ShiftMCQEasy📈 Topic in 14% papers+4−1
Ques. 1JEE Main 2024, 4 April (Morning Shift)

Let , R. Let the mean and the variance of 6 observations -3, 4, 7,-6, , be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is :

  1. 163
  2. 113
  3. 143
  4. 133

Answer

(4) 133

Solution

Mean: 2+ + 6=2 + =10

Variance: xi26-22=23 xi2=162

110+ 2+ 2=162 2+ 2=52 = 100-522=24

\ , \=\4, 6\

M.D. = |xi-2|6= 5+2+5+8+2+46= 266= 133

Answer: (4)

Keep practising — Statistics

Ques. 2JEE Main 2024, 1 February (Morning Shift)

Let the median and the mean deviation about the median of 7 observations 170, 125, 230, 190, 210, a, b be 170 and 2057 respectively. Then the mean deviation about the mean of these 7 observations is :

  1. 31
  2. 28
  3. 30
  4. 32
Ques. 3JEE Main 2024, 1 February (Evening Shift)

Consider 10 observations x1, x2, , x10 such that i=110 (xi- )=2 and i=110 (xi- )2=40, where , are positive integers. Let the mean and the variance of the observations be 65 and 8425 respectively. Then is equal to :

  1. 2
  2. 1
  3. 52
  4. 32
Ques. 4JEE Main 2024, 31 January (Evening Shift)

Let the mean and the variance of 6 observations a, b, 68, 44, 48, 60 be 55 and 194, respectively. If a>b, then a+3b is

  1. 180
  2. 210
  3. 190
  4. 200
Ques. 5JEE Main 2024, 30 January (Morning Shift)

Let M denote the median of the following frequency distribution [figure] Then 20M is equal to :

  1. 104
  2. 52
  3. 208
  4. 416
Ques. 6JEE Main 2024, 30 January (Evening Shift)

The variance 2 of the data [figure] is .

Ques. 7JEE Main 2024, 29 January (Morning Shift)

If the mean and variance of the data 65,68,58,44,48,45,60, , ,60 where > , are 56 and 66.2 respectively, then 2+ 2 is equal to .

Ques. 8JEE Main 2024, 29 January (Evening Shift)

If the mean and variance of five observations are 245 and 19425 respectively and the mean of the first four observations is 72, then the variance of the first four observations is equal to

  1. 54
  2. 45
  3. 1054
  4. 7712
Ques. 9JEE Main 2024, 27 January (Morning Shift)

Let a1, a2, a10 be 10 observations such that k=110 ak=50 and k<j ak aj=1100. Then the standard deviation of a1, a2, , a10 is equal to :

  1. 5
  2. 115
  3. 10
  4. 5
Ques. 10JEE Main 2024, 27 January (Evening Shift)

The mean and standard deviation of 15 observations were found to be 12 and 3 respectively. On rechecking it was found that an observation was read as 10 in place of 12 . If and 2 denote the mean and variance of the correct observations respectively, then 15 ( + 2+ 2 ) is equal to .

All Statistics PYQs →

PDFDownload Statistics PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters