A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is 20 cm away from the mirror. The length of the image is
- 10 cm
- 15 cm
- 2.5 cm
- 5 cm
Answer
(4) 5 cm
Solution
For the concave mirror, f = -10 cm; mirror formula: 1v + 1u = 1f
Near end: u1 = -20 cm (at 2f)
⇒ 1v1 = - 110 + 120 = - 120 ⇒ v1 = -20 cm
Far end: u2 = -30 cm
⇒ 1v2 = - 110 + 130 = - 230 ⇒ v2 = -15 cm
∴ Length of the image = |v1 - v2| = 20 - 15 = 5 cm
Answer: (4)