Let A be a 2 2 symmetric matrix such that A bmatrix1\\1 bmatrix = bmatrix3\\7 bmatrix and the determinant of A be 1. If A-1 = A + I, where I is an identity matrix of order 2 2, then + equals .
Answer
5
Solution
Let A = bmatrixa & b\ & d bmatrix (symmetric), so a + b = 3 and b + d = 7.
|A| = 1 (3 - b)(7 - b) - b2 = 1 21 - 10b = 1 b = 2, hence a = 1, d = 5
A = bmatrix1 & 2\\2 & 5 bmatrix and A-1 = adj A|A| = bmatrix5 & -2\\-2 & 1 bmatrix
Also A + I = bmatrix + & 2 \\2 & 5 + bmatrix; comparing it with A-1 entry by entry:
2 = -2 = -1, and + = 5 = 6 (check: 5 + = 1)
+ = 5
Answer: 5