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Matrices

JEE Main 2024 (Online) 4th April Evening ShiftNumericalEasy📈 Topic in 7% papers+4
Ques. 1JEE Main 2024, 4 April (Evening Shift)

Let A be a 2 2 symmetric matrix such that A bmatrix1\\1 bmatrix = bmatrix3\\7 bmatrix and the determinant of A be 1. If A-1 = A + I, where I is an identity matrix of order 2 2, then + equals .

Answer

5

Solution

Let A = bmatrixa & b\ & d bmatrix (symmetric), so a + b = 3 and b + d = 7.

|A| = 1 (3 - b)(7 - b) - b2 = 1 21 - 10b = 1 b = 2, hence a = 1, d = 5

A = bmatrix1 & 2\\2 & 5 bmatrix and A-1 = adj A|A| = bmatrix5 & -2\\-2 & 1 bmatrix

Also A + I = bmatrix + & 2 \\2 & 5 + bmatrix; comparing it with A-1 entry by entry:

2 = -2 = -1, and + = 5 = 6 (check: 5 + = 1)

+ = 5

Answer: 5

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Ques. 2JEE Main 2024, 1 February (Evening Shift)

Let A=I2-2MMT, where M is a real matrix of order 2 1 such that the relation MTM=I1 holds. If is a real number such that the relation AX= X holds for some non-zero real matrix X of order 2 1, then the sum of squares of all possible values of is equal to .

Ques. 3JEE Main 2024, 29 January (Morning Shift)

Let A be a square matrix such that AAT=I. Then 12A [ (A+AT )2+ (A-AT )2 ] is equal to

  1. A2+AT
  2. A3+I
  3. A3+AT
  4. A2+I
Ques. 4JEE Main 2024, 27 January (Morning Shift)

Consider the matrix f(x)= bmatrix x & - x & 0\ x & x & 0\ 0 & 0 & 1 bmatrix. Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are false
  3. Both Statement I and Statement II are true
  4. Statement I is true but Statement II is false
Ques. 5JEE Main 2024, 27 January (Evening Shift)

Let A be a 2 2 real matrix and I be the identity matrix of order 2. If the roots of the equation |A-xI|=0 be -1 and 3, then the sum of the diagonal elements of the matrix A2 is .

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