Let A = bmatrix 3 & -4 \ 1 & -1 bmatrix and B be two matrices such that A100 = 100B + I. Then the sum of all the elements of B100 is
Answer
0
Solution
Write A = I + N, where N = A - I = bmatrix 2 & -4 \ 1 & -2 bmatrix
N2 = bmatrix 4 - 4 & -8 + 8 \ 2 - 2 & -4 + 4 bmatrix = O
IN = NI, by the binomial theorem: A100 = I + 100N (all higher powers of N vanish)
100B + I = I + 100N B = N
B100 = N100 = O
Sum of all the elements of B100 = 0
Answer: 0