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Trigonometric Functions · Question 21

JEE Main 2025 (Online) 7th April Morning ShiftMCQMedium📈 Topic in 19% papers+4−1
1

If for [- 3, 0 ], the points (x, y) = (3 ( + 3 ), 2 ( + 6 ) ) lie on xy + x + y + = 0, then 2 + 2 + 2 is equal to :

  1. 75
  2. 96
  3. 80
  4. 72

Answer

(1) 75

Solution

Let = + 3, so = x3 and + 6 = - 6.

y2 = ( - 6 ) = - 1 31 + 3 = 3 - 1 3 +

y2 = 3x3 - 1 3 + x3 = 3x - 3x + 3 3

xy + 3 3y = 2 3x - 6

xy - 2 3x + 3 3y + 6 = 0

= -2 3, = 3 3, = 6

2 + 2 + 2 = 12 + 27 + 36 = 75

Answer: (1)

JEE Main 2025 (Online) 7th April Morning Shift

Keep practising — Trigonometric Functions

2

The number of solutions of the equation 2 2 + 5 2 = 2 3 5 2 in [- 2, 2 ] is :

  1. 5
  2. 7
  3. 6
  4. 9
JEE Main 2025 (Online) 7th April Evening Shift
3

If 10 4 + 15 4 = 6, then the value of 27 cosec6 + 8 6 16 8 is

  1. 25
  2. 35
  3. 15
  4. 34
JEE Main 2025 (Online) 4th April Morning Shift
4

The number of solutions of the equation 2x + 3 x = , x [-2 , 2 ] - \ 2, 3 2 \ is:

  1. 4
  2. 5
  3. 3
  4. 6
JEE Main 2025 (Online) 3rd April Morning Shift
5

The number of solutions of the equation (4 - 3) x - 2 3 2 x = - 41 + 3, x [-2 , 5 2 ] is

  1. 4
  2. 3
  3. 6
  4. 5
JEE Main 2025 (Online) 3rd April Evening Shift
6

If [-2 , 2 ], then the number of solutions of 2 2 2 + (2 - 6) - 3 = 0, is equal to:

  1. 8
  2. 6
  3. 10
  4. 12
JEE Main 2025 (Online) 2nd April Morning Shift
7

If [- 7 6, 4 3 ], then the number of solutions of 3 cosec2 - 2( 3 - 1) cosec - 4 = 0, is equal to :

  1. 7
  2. 10
  3. 6
  4. 8
JEE Main 2025 (Online) 2nd April Evening Shift
8

If r=113 \ 1 ( 4 + (r - 1) 6 ) ( 4 + r 6 ) \ = a 3 + b, a, b Z, then a2 + b2 is equal to :

  1. 10
  2. 4
  3. 8
  4. 2
JEE Main 2025 (Online) 28th January Evening Shift

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