For (i) I-, (ii) Cl-, (iii) Br-, the increasing order of nucleophilicity would be
- Cl- < Br- < I-
- I- < Cl- < Br-
- Br- < Cl- < I-
- I- < Br- < Cl-
Answer
(1) Cl- < Br- < I-
Solution
In a polar protic solvent (water, alcohol) the halide ions are solvated by hydrogen bonding.
∵ Cl- is the smallest ion, it is solvated most strongly and its lone pairs are least available; I- is the largest, least solvated and most polarisable ion.
⇒ Nucleophilicity increases down the group: Cl- < Br- < I-
∴ The correct increasing order is (ii) < (iii) < (i).
Answer: (1)