The temperature inside a refrigerator is t2 C and the room temperature is t1 C. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
- t1t1 - t2
- t1 + 273t1 - t2
- t2 + 273t1 - t2
- t1 + t2t1 + 273
Answer
(2) t1 + 273t1 - t2
Solution
For an ideal (Carnot) refrigerator: Q1Q2 = T1T2 and W = Q1 - Q2
Q1W = T1T1 - T2
With T1 = t1 + 273 and T2 = t2 + 273: T1 - T2 = t1 - t2
Heat delivered to the room per joule = t1 + 273t1 - t2
Answer: (2)