The photoelectric threshold wavelength of silver is 3250 10-10 m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536 10-10 m is [Given h = 4.14 10-15 eV s and c = 3 108 m s-1]
- 0.6 106 m s-1
- 61 103 m s-1
- 0.3 106 m s-1
- 6 105 m s-1
Answer
(1) 0.6 106 m s-1, (4) 6 105 m s-1
Solution
Einstein's equation: 12mv2 = hc ( 1 - 1 0 )
hc = 4.14 10-15 3 108 = 1.242 10-6 eV m
12mv2 = 1.242 10-6 ( 12536 10-10 - 13250 10-10 )
1.08 eV = 1.72 10-19 J
v = 2 1.72 10-199.1 10-31
6.1 105 m s-1
v 0.6 106 m s-1 = 6 105 m s-1 — options (1) and (4) express the same value.
Answer: (1), (4)