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Let ( + ) = - 110 and ( - ) = 38, where 0 < < 3 and 0 < < 4. If 2 = 3(1 - r 5) 11(s + 5), r, s N, then r + s is equal to .
20
0 < + < 7 12 and ( + ) < 0 ( + ) = 1 - 1100 = 3 1110
( + ) = -3 11
- 4 < - < 3 ( - ) = 1 - 964 = 558
( - ) = 3 55
2 = [( + ) + ( - )] = -3 11 + 3 551 + 3 11 3 55
= -3 11 55 + 3 55 + 9 11 = 3 - 33 5 11( 5 + 9)
= 3(1 - 11 5) 11(9 + 5)
r = 11, s = 9 r + s = 20
Answer: 20
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