An ac circuit contains a resistance of 1 kΩ, a capacitor of 0.1 μF and an inductor of 1 mH connected in series. The resonance frequency of the circuit is approximately :
- 15.9 kHz
- 20.7 kHz
- 10.1 kHz
- 13.5 kHz
Answer
(1) 15.9 kHz
Solution
At resonance XL = XC ⇒ f0 = 12 LC (independent of R)
LC = 10-3 0.1 10-6 = 10-10 = 10-5 s
⇒ f0 = 12 10-5 = 1056.28
≈ 15900 Hz ≈ 15.9 kHz
Answer: (1)