An ac voltage V = 220 (2 103 t) Volt is applied to a series LCR circuit. Then the current amplitude in this circuit is: (Given : L = 10 mH, C = 25 , R = 100 )
- 22.0 A
- 2.2 A
- 5.5 A
- 11.0 A
Answer
(2) 2.2 A
Solution
Here, = 2 103 rad s-1 and V0 = 220 V.
Inductive reactance:
XL = L = 2 103 10 10-3 = 20
Capacitive reactance:
XC = 1 C = 12 103 25 10-6 = 20
Since XL = XC, the circuit is in resonance:
Z = R = 100
Current amplitude:
I0 = V0Z = 220100 = 2.2 A
Answer: (2)